WebThe coefficient of performance (COP) of reversible or irreversible refrigerator or heat pump is given by. COP R = 1/ ( (Q H /Q L )-1) COP HP = 1/ (1- (Q L /Q H )) where. Q H = the amount of heat rejected to the. high-temperature reservoir. Q L = the amount of heat received from the. low-temperature reservoir. WebTranscribed Image Text: A refrigerator uses refrigerant-134a as the working fluid and operates on the ideal vapor- compression refrigeration cycle except for the compression process as shown in Figure Q1. The refrigerant enters the evaporator at 120 kPa with a quality of 34 percent and leaves the compressor at 70°C. If the compressor consumes …
Coefficient of Performance Calculator
Weba) Determine the COP of the refrigerator. b) Determine the mass flow rate [kg/hr] of the cooled water that can be produced at the prescribed temperature. c) Determine the rate of entropy generation in the compressor and the expansion valve. d) Determine the second law of efficiency of the cycle, which is the ratio the current coefficient of ... WebMar 17, 2015 · Coefficient Of Performance (COP) is the ratio of "Coldness" produced to the "Heat" or " Work" supplied. In the case of vapour compression system, it is the mechanical or electrical work , … five letter word starting with aa
Solved Refrigerant-134a enters the compressor of a Chegg.com
Web2296, Page 4 International Refrigeration and Air Conditioning Conference at Purdue, July 12-15, 2010 where ûp cab=K ffm ff 2=K fzm fz 2 is the pressure drop in both the frozen- and fresh-food compartments (see Fig. 3), and ûp fan is the pressure head provided by the fan, which was correlated as follows (Waltrich, 2008), Δ = 3 i 0 i p fan e i m fan (13) The … WebAnswer (1 of 3): COP ( coeficient of performance ) is the ratio between the Q quantity of heat transferred or removed from a refrigerator system and the W the energy necessary to input into the refrigerator system to produce or remove the quantity of heat from the system. Generally W is more than... WebIt includes measurements of the thermal insulation of a typical refrigerator cabinet (1.21 W/K for the freezer, 0.88 W/K for the refrigerated compartment). From Table 3 of that publication, I find a COP of about 1.7 - suggesting that for our example 1.7*25 W = 42 W of heat is extracted, and 42W+25W = 67 W is rejected five letter word starting w